Original content Copyright © by Houghton Mifflin Harcourt. Additions and changes to the original content are the responsibility of the instructor. Distance and Midpoint Formulas Segment with endpoints at (−4, 10) and (−6, −2) _____________________ 4. Segment with endpoints at (−1, 15) and (3, 0) _____________________ 5. Segment with endpoints at (2, −3) and (−2, −5)

Answer: a) D = √148                  m = (-5,4)b) D = √241 m = (1, 7.5)c) D = √20m = (0,-4)Step-by-step explanation: Distance and Midpoint Formulasdistance = D = √[(x₂-x₁)² + (y₂-y₁)²]Midpoint: m = ((x₂+x₁)/2 , (y₂+y₁)/2)(−4, 10) and (−6, −2) D = √[(-6-(-4))² + (-2-10)²] = √[(-6+4))² + (-2-10)²] = √[(-2))² + (-12)²] =√[4 + 144] = √148m = ((-6+(-4))/2 ; (-2+10)/2m = (-10/2 ; 8/2) m = (-5,4)(−1, 15) and (3, 0)D = √[(3-(-1))² + (0-15)²] = √[(3+1))² + (0-15)²] = √[(4)² + (-15)²] =√[16 + 225] = √241m = ((3+(-1))/2 ; (0+15)/2m = (2/2 ; 15/2) m = (1,7.5)(2, −3) and (−2, −5)D = √[(-2-2)² + ((-5)-(-3)²] = √[(-4))² + (-5+3)²] = √[(-4)² + (-2)²] =√[16 + 4] = √20m = (-2+2))/2 ; (-5+(-3))/2m = (0/2 ; -8/2) m = (0,-4)