The quality control engineer for a furniture manufacturer is interested in the mean amount of force necessary to produce cracks in stressed oak furniture. she performs a two-tail test of the null hypothesis that the mean for the stressed oak furniture is 650. the calculated value of the z test statistic is a positive number that leads to a p-value of 0.080 for the test. 22 referring to scenario 9-6, suppose the engineer had decided that the alternative hypothesis to test was that the mean was greater than 650. what would be the p-value of this one-tail test? 0.040 0.960 0.840 0.160
Accepted Solution
A:
Hello.
Since the calculated p-value for a two-tailed test is 0.080, the p-value of a one-tailed test is half of it, which is 0.040.
Remember that the p-value is the area of the rejection region under the normal curve. The p-value of a two-tailed test will double the p-value of a single-tailed test considering all parameters to be the same.