In physics, if a moving object has a starting position at so, an initial velocity of vo, and a constant acceleration a, thethe position S at any time t>O is given by:S = 1/2 at ^2 + vot+soSolve for the acceleration, a, in terms of the other variables. For this assessment item, you can use^to show exponentand type your answer in the answer box, or you may choose to write your answer on paper and upload it.

Answer:[tex]a=\frac{2S -2v_ot-2s_o}{t^2}[/tex]Step-by-step explanation:We have the equation of the position of the object[tex]S = \frac{1}{2}at ^2 + v_ot+s_o[/tex]We need to solve the equation for the variable a[tex]S = \frac{1}{2}at ^2 + v_ot+s_o[/tex]Subtract [tex]s_0[/tex] and [tex]v_0t[/tex] on both sides of the equality[tex]S -v_ot-s_o = \frac{1}{2}at ^2 + v_ot+s_o - v_ot- s_o[/tex][tex]S -v_ot-s_o = \frac{1}{2}at ^2[/tex]multiply by 2 on both sides of equality[tex]2S -2v_ot-2s_o = 2*\frac{1}{2}at ^2[/tex][tex]2S -2v_ot-2s_o =at ^2[/tex]Divide between [tex]t ^ 2[/tex] on both sides of the equation[tex]\frac{2S -2v_ot-2s_o}{t^2} =a\frac{t^2}{t^2}[/tex]Finally[tex]a=\frac{2S -2v_ot-2s_o}{t^2}[/tex]