What is the solution to the system of equations below? y=-2x-6 and 2y=4x-12​

Answer:{x = 0 , y = -6Step-by-step explanation:Solve the following system: {y = -2 x - 6 | (equation 1) {2 y = 4 x - 12 | (equation 2) Express the system in standard form: {2 x + y = -6 | (equation 1) {-(4 x) + 2 y = -12 | (equation 2) Swap equation 1 with equation 2: {-(4 x) + 2 y = -12 | (equation 1) {2 x + y = -6 | (equation 2) Add 1/2 × (equation 1) to equation 2: {-(4 x) + 2 y = -12 | (equation 1) {0 x+2 y = -12 | (equation 2) Divide equation 1 by 2: {-(2 x) + y = -6 | (equation 1) {0 x+2 y = -12 | (equation 2) Divide equation 2 by 2: {-(2 x) + y = -6 | (equation 1) {0 x+y = -6 | (equation 2) Subtract equation 2 from equation 1: {-(2 x)+0 y = 0 | (equation 1) {0 x+y = -6 | (equation 2) Divide equation 1 by -2: {x+0 y = 0 | (equation 1) {0 x+y = -6 | (equation 2) Collect results: Answer:  {x = 0 , y = -6